Linux glibc幽灵漏洞修复方法

关于这个漏洞网上很多介绍,在这里就不说了，想了解的童鞋点击下面的连接

CVE-2015-0235：Linux Glibc幽灵漏洞允许黑客远程获取系统权限

测试漏洞是否存在: 

把下面的代码保存为gistfile1.c

#include <netdb.h>  #include <stdio.h>  #include <stdlib.h>  #include <string.h>  #include <errno.h>     #define CANARY "in_the_coal_mine"     struct {    char buffer[1024];    char canary[sizeof(CANARY)];  } temp = { "buffer", CANARY };     int main(void) {    struct hostent resbuf;    struct hostent *result;    int herrno;    int retval;       /*** strlen (name) = size_needed - sizeof (*host_addr) - sizeof (*h_addr_ptrs) - 1; ***/    size_t len = sizeof(temp.buffer) - 16*sizeof(unsigned char) - 2*sizeof(char *) - 1;    char name[sizeof(temp.buffer)];    memset(name, '0', len);    name[len] = '\0';       retval = gethostbyname_r(name, &resbuf, temp.buffer, sizeof(temp.buffer), &result, &herrno);       if (strcmp(temp.canary, CANARY) != 0) {      puts("vulnerable");      exit(EXIT_SUCCESS);    }    if (retval == ERANGE) {      puts("not vulnerable");      exit(EXIT_SUCCESS);    }    puts("should not happen");    exit(EXIT_FAILURE);  }  #* from http://www.openwall.com/lists/oss-security/2015/01/27/9 */

然后在服务器上执行：

 gcc gistfile1.c -o CVE-2015-0235   ./CVE-2015-0235

如果提示:vulnerable 就说明存在漏洞.

修复方法:

执行这些命令即可

yum clean all   yum makecache  yum -y install glibc* 

来自：http://blog.csdn.net/sikers/article/details/43230503