Android获取本地IP地址 .
jopen
11年前
首先说明,这个是察看WIFI的IP地址的方法,还需要添加User Permission(android.permission.ACCESS_WIFI_STATE):
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以下是详细解释这个方法:
而NetworkUtils.inetAddressToInt(mIpAddress)是
private String getlocalip(){ WifiManager wifiManager = (WifiManager)getSystemService(Context.WIFI_SERVICE); WifiInfo wifiInfo = wifiManager.getConnectionInfo(); int ipAddress = wifiInfo.getIpAddress(); Log.d(Tag, "int ip "+ipAddress); if(ipAddress==0)return null; return ((ipAddress & 0xff)+"."+(ipAddress>>8 & 0xff)+"." +(ipAddress>>16 & 0xff)+"."+(ipAddress>>24 & 0xff)); }
以下是详细解释这个方法:
在这里,我们可以是察看WifiInfo中的信息即WifiInfo.getIpAddress(),将返回一个int型的IP地址,我们可以看看源代码:
public int getIpAddress() { if (mIpAddress == null || mIpAddress instanceof Inet6Address) return 0; return NetworkUtils.inetAddressToInt(mIpAddress); }
而NetworkUtils.inetAddressToInt(mIpAddress)是
public static int inetAddressToInt(InetAddress inetAddr) throws IllegalArgumentException { byte [] addr = inetAddr.getAddress(); if (addr.length != 4) { throw new IllegalArgumentException("Not an IPv4 address");} return ((addr[3] & 0xff) << 24) | ((addr[2] & 0xff) << 16) | ((addr[1] & 0xff) << 8) | (addr[0] & 0xff);
所以,获取到了这个int型的IP地址,我们就还得做一次转换: